SoFunction
Updated on 2025-03-01

Golang implements the example steps for reading 32GB large files in seconds

Go handles large files

In Go, when processing large files, chunk reading is generally used to avoid loading the entire file into memory at one time.

Brief steps

Here are the simple steps to read large files:

Open the file:useOpen the file.

file, err := ("")
if err != nil {
    (err)
}
defer ()

Get file information:useGet basic information about the file, including file size.

fileInfo, err := ()
if err != nil {
    (err)
}
fileSize := ()

Set the buffer size:To improve read efficiency, use buffers of appropriate size.

bufferSize := 8192 // 8KB buffer sizebuffer := make([]byte, bufferSize)

Looping the file content:useLoop to read the file content.

for {
    bytesRead, err := (buffer)
    if err ==  {
        // The file is finished reading        break
    }
    if err != nil {
        (err)
    }

    // Process the read data, for example output to the console    (string(buffer[:bytesRead]))
}

Close the file:Close the file after reading is completed.

()

Complete example

Here is a complete example code for reading large files:

package main
import (
    "bufio"
    "log"
    "os"
)
func main() {
    file, err := ("large_file.txt")
    if err != nil {
        (err)
    }
    defer ()
    const maxScanTokenSize = 64 * 1024 * 1024 // 64MB
    buf := make([]byte, maxScanTokenSize)
    scanner := (file)
    (buf, maxScanTokenSize)
    for () {
        line := ()
        // Process the logic of each line    }
    if err := (); err != nil {
        (err)
    }
}

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