C# calls exe parameter and gets an instance of the printed value

Calling method:

string baseName = ();
 // baseName+"/"
 // string fileName = @"C:\Users\59930\Desktop\20170605\WindowsFormsApp1\WindowsFormsApp1\WindowsFormsApp1\bin\x86\Debug\";
 string fileName = baseName + @"\";
 string para = " " + code;          
 Process p = new Process();
  = false;
  = true;
  = fileName;
  = true;
  = para;//The parameters are separated by spaces. If a parameter is empty, you can pass in "" ();
 ();
 string output = ();

Write in the called exe return value

(mmma);

Supplement: The methods of calling external exe in c# are simple and complex.

The easiest thing is to directly use the process class

using ;
(" ");

If you want to set it up in detail,

  public static void RunExeByProcess(string exePath, string argument)
  {
   //Create a process    process = new ();
   //The name of the called exe    = exePath;
   //Pass the parameters of the exe    = argument;
    = false;
   //Do not display the exe interface    = true;
    = true;
    = true;
   ();
 
    = true;
   //Blocking and waiting for the call to end   ();
  }

If you want to get the result returned by the caller, you only need to modify the above slightly to increase the return value:

public static string RunExeByProcess(string exePath, string argument)
  {
   //Create a process    process = new ();
   //The name of the called exe    = exePath;
   //Pass the parameters of the exe    = argument;
    = false;
   //Do not display the exe interface    = true;
    = true;
    = true;
   ();
 
    = true;
 
   string result = null;
   while (!)
   {
    result += () + ;
   }
   ();
   return result;
  }

The above is personal experience. I hope you can give you a reference and I hope you can support me more. If there are any mistakes or no complete considerations, I would like to give you advice.