This article describes the method of C# implementing input 10 numbers stored in an array and finding max, min and average numbers. Share it for your reference, as follows:
using System; using ; using ; using ; namespace ConsoleApplication1 { class Program { static void Main(string[] args) { int nu1, max,min,number; int[] str = new int[10]; for (nu1 = 0; nu1<10; nu1++) str[nu1] = (()); max = str[0]; min = str[1]; number = 0; for (nu1 = 0; nu1 < 10; nu1++) { number += str[nu1]; if (str[nu1] > max) max = str[nu1]; if (str[nu1] < min) min = str[nu1]; } number /= 10; ("max is :{0}",max); ("min is :{0}", min); ("pingjun is :{0}", number); (); } } }
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Online unary function (eq) solution calculation tool:
http://tools./jisuanqi/equ_jisuanqi
Scientific Calculator Online Use_Advanced Calculator Online Calculator:
http://tools./jisuanqi/jsqkexue
Online Calculator_Standard Calculator:
http://tools./jisuanqi/jsq
For more information about C#, you can also view the special topic of this site: "Summary of C# string operation skills》、《C# data structure and algorithm tutorial》、《Tutorial on the usage of common C# controls》、《Summary of WinForm control usage》、《Summary of thread usage techniques for C# programming》、《Summary of C# array operation skills"and"Introduction to C# object-oriented programming tutorial》
I hope this article will be helpful to everyone's C# programming.