Use of () method:
- mkString(seq:String) method is to split the original string using a specific string seq.
- mkString(statt:String,seq:String,end:String) method is to split the original string using a specific string seq while adding the string start before the original string and add the string end after it.
object Test {
def main(args: Array[String]): Unit = {
var name : String = "Hello LittleLawson"
var age :Int = 2
println()
println((" "))//separate string with space
var str0 = "scala"
println((","))//separate string with comma
println(("begin",",","end"))
/*
is used in the inner List,That is say ,Elements in the list is applied.
*/
val a = List(1,2,3,4)
val b = new StringBuilder()
println(("List(" , ", " , ")"))
}
}
The execution results are as follows:
Hello LittleLawson
H e l l o L i t t l e L a w s o n
s,c,a,l,a
begins,c,a,l,aend
List(1, 2, 3, 4)Process finished with exit code 0
Convert a collection into a string through the mkString method
Problem
If you want to convert collection elements into strings, you may also add delimiters, prefixes, and suffixes.
Solution
Use the mkString method to print a collection content. Here is a simple example:
scala> val a = Array("apple", "banana", "cherry")
a: Array[String] = Array(apple, banana, cherry)
scala>
res3: String = applebananacherry
Use the mkString method to see that the result is not beautiful, let's add a separator:
scala> (",")
res4: String = apple,banana,cherry
scala> (" ")
res5: String = apple banana cherry
This will look much better, and you can also add a prefix and a suffix:
scala> ("[", ", ", "]")
res6: String = [apple, banana, cherry]
If you want to convert an abscond collection into a string, such as a nested array, first you need to expand the nested array and then call the mkString method:
scala> val a = Array(Array("a", "b"), Array("c", "d"))
a: Array[Array[String]] = Array(Array(a, b), Array(c, d))
scala> (",")
res7: String = a,b,c,d
Discussion
You can call the toString method of the collection, but it returns the name of the collection with the information of the collection element:
scala> val v = Vector("apple", "banana", "cherry")
v: [String] = Vector(apple, banana, cherry)
scala>
res8: String = Vector(apple, banana, cherry)
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