Copy the codeThe code is as follows:
#include <>
int main(int argc, char *argv[])
{
unsigned int max_int = 0-1;
printf("The max value of unsigned int on 32 machine: %u/n", max_int);
}
Copy the codeThe code is as follows:
#include <>
int main(int argc, char *argv[])
{
unsigned int max_int = 0-1;
printf("The max value of unsigned int on 32 machine: %u/n", max_int);
}
After gcc is compiled:
int_sizeof1.c: In function 'main':
int_sizeof1.c:5: Warning: integer overflow
After running:
The max value of int on 32 machine: 4294967295
After VC6.0 and java are compiled, there are no errors.
After running:
The max value of int on 32 machine: 4294967295
Copy the codeThe code is as follows:
#include <>
int main(int argc, char *argv[])
{
int max_int = (1<<31)-1;
printf("The max value of int on 32 machine: %d/n", max_int);
}
The program for writing its int into a signed type is as follows:
Copy the codeThe code is as follows:
#include <>
int main(int argc, char *argv[])
{
int max_int = (1<<31)-1;
printf("The max value of int on 32 machine: %d/n", max_int);
}
After gcc is compiled:
int_sizeof1.c: In function 'main':
int_sizeof1.c:5: Warning: integer overflow
After running:
The max value of int on 32 machine: 2147483647
After VC6.0 and java are compiled, there are no errors.
After running:
The max value of int on 32 machine: 2147483647
Because the highest bit of int is the sign bit.