C language realization of card game (kitten fishing)

// Card game - kitten fishing - queue stack - (so-called pulling train)#include <>

struct queue   //queue{
 int data[1000];
 int head;
 int tail;
}; 
struct stack   //Stack{
 int data[10];
 int top;
};

int main(void)
{
 struct queue q1, q2; //The queues of Xiaoheng q1 and Xiaohan q2 struct stack s;  //Stack int book[10];   //Record, determine whether it appears the second time int i, t;
 
  = 1,  = 1;  //Initialize the queue  = 1,  = 1; 
 
  = 0;     //Initialize the stack 
 for(i = 1;i <= 9;i++)  //The number of initialization occurrences is 0 book[i] = 0;
 
 for(i = 1; i <= 6; i++) {  //Give a person here 6 cards scanf("%d", &[]);
 ++;
 }
 for(i = 1;i <= 6;i++) {
 scanf("%d", &[]);
 ++;
 } 
 
 while( <  &&  <  ) {  //Execute loop when the queue is not empty t = [];   //Xiaohen (first) plays the cards if(book[t] == 0){    //When there is no such card on the table ++;    //Get this card in team //++;
 [++] = t;  //Put the played cards into the stack book[t] = 1;    //Tag this table already has }else{      //It's already available on this table, Xiaohen can win ++;    //The card you will play will be played to team [] = t; //Put this card to the end of the team ++;
 
 while([] != t) { //Retract the winning cards on the table, and there is no last card here. book[[]] = 0;   //Cancel mark [] = []; //Put it at the end of the team in turn ++;
 --;       //A card is missing in the stack, so--1 }
 //Retract the t card on the table book[t] = 0;
 [] = t;
 ++;
 --; 
 }
 
 if( ==  )   //If Xiaoheng is finished playing, the game is over break; 
 
 //It's Xiao Ha's turn to play cards, and make a judgment like Xiao Heng t = [];
 if(book[t] == 0) {
 ++;
 ++;
 [] = t;
 book[t] = 1;
 } 
 else {
 ++;
 [] = t;
 ++;
 
 while([] != t) {
 book[[]] = 0;
 [] = [];
 ++;
 --;
 } 
 
 book[t] = 0;
 [] = t;
 ++;
 --;
 } 
 } 
 
 if( ==  ) {
 printf("Small Hum win \n");
 printf("Xiaohen's current card is");
 for(i = ;i < ;i++)
 printf(" %d",[i]);
 
 if() {  //If there is a card on the table printf("\nThe card on the table is");
 for(i = 1;i <= ;i++)
 printf(" %d",[i]);
 printf("\n"); 
 }
 else
 printf("\nThere are no cards on the table");
 } else {
 printf("Xiao Ha win \n");
 printf("Xiao Ha's current card is");
 for(i = ;i <= -1;i++)
 printf(" %d", [i]);
 
 if() {  //If there is a card on the table printf("\nThe card on the table is");
 for(i = 1;i <= ;i++)
 printf(" %d",[i]);
 printf("\n"); 
 } else
 printf("\nThere are no cards on the table");
 } 
 
 return 0;
} 
/*Code Running Results
 1 2 3 4 5 6
 3 2 1 5 2 6
 Little Ha win
 Xiao Ha's current card is 5 6 2 3 1 3 2 5 2
 The card on the table is 4 6 1
 */