Basic NSURL operations for IOS development

Basic NSURL operations for IOS development

NSURL is actually the website address we see on the browser. Isn’t this just a string? Why do you still need to write an NSURL? It’s mainly because the strings of the website address are relatively complex, including many request parameters. In this way, each department needs to be parsed during the request process, so encapsulating an NSURL is very convenient to operate:

NSURL *url = [NSURL URLWithString:@"/s?tn=baiduhome_pg&bs=NSRUL&f=8&rsv_bp=1&rsv_spt=1&wd=NSurl&inputT=2709"]; 
   
  NSLog(@"Scheme: %@", [url scheme]); 
   
  NSLog(@"Host: %@", [url host]); 
   
  NSLog(@"Port: %@", [url port]); 
   
  NSLog(@"Path: %@", [url path]); 
   
  NSLog(@"Relative path: %@", [url relativePath]); 
   
  NSLog(@"Path components as array: %@", [url pathComponents]); 
   
  NSLog(@"Parameter string: %@", [url parameterString]); 
   
  NSLog(@"Query: %@", [url query]); 
   
  NSLog(@"Fragment: %@", [url fragment]); 
   
  NSLog(@"User: %@", [url user]); 
   
  NSLog(@"Password: %@", [url password]);

result:

2012-08-29 15:52:23.781 NSurl[3560:f803] Scheme: http 
2012-08-29 15:52:32.793 NSurl[3560:f803] Host:  
2012-08-29 15:52:39.102 NSurl[3560:f803] Port: (null) 
2012-08-29 15:52:42.590 NSurl[3560:f803] Path: /s 
2012-08-29 15:52:52.516 NSurl[3560:f803] Relative path: /s 
2012-08-29 15:53:05.576 NSurl[3560:f803] Path components as array: ( 
  "/", 
  s 
) 
2012-08-29 15:53:32.861 NSurl[3560:f803] Parameter string: (null) 
2012-08-29 15:53:37.528 NSurl[3560:f803] Query: tn=baiduhome_pg&bs=NSRUL&f=8&rsv_bp=1&rsv_spt=1&wd=NSurl&inputT=2709 
2012-08-29 15:53:52.942 NSurl[3560:f803] Fragment: (null) 
2012-08-29 15:53:54.539 NSurl[3560:f803] User: (null) 
2012-08-29 15:53:57.808 NSurl[3560:f803] Password: (null)

Thank you for reading, I hope it can help you. Thank you for your support for this site!