Summary of output formatting problems in Java

In Java, output formatting is a very important function, especially in scenarios where precise control of the output format is required.

Here is a detailed explanation of the output part in the code:

Output in the original code:

("%.6f\n", l);

Detailed explanation:

：It is a method used in Java to format output, similar to the one in C/C++printffunction.
It can format the output data according to the specified format string.
Format string%.6f：
%.6fis a formatted placeholder that specifies the output format of floating point numbers. in:
%Indicates the beginning of the formatting placeholder.
.6Denotes that 6 digits are retained after the decimal point.
fRepresents a floating-point number.

Output result:

("%.6f\n", l);Meaning:
Add variableslThe value of   is formatted as a floating point, and the 6-digit number is retained after the decimal point, and the line break is output.

For example, iflThe value of the value is 2.12345678, and the output will be:

2.123457

Line breaks\n:

\nis a newline character, used to break lines after output.
In Java, line breaks are represented in the same way as in C/C++.
Other formatting options:
If more flexible formatting is required, other formatting placeholders can be used, such as:

%.2f: Keep 2 decimal places.
%d: Output integer.
%s: Output string.
%e: Output floating point numbers using scientific notation.

Sample code:

public class Main {
   public static void main(String[] args) {
       double num = 123.456789;
       int integer = 123;
       String str = "Hello";
       // Floating point number, retaining 6 decimal places       ("%.6f\n", num); // Output: 123.456789       // Floating point number, retaining 2 decimal places       ("%.2f\n", num); // Output: 123.46       // Integer       ("%d\n", integer); // Output: 123       // String       ("%s\n", str); // Output: Hello       // Scientific Counting Method       ("%e\n", num); // Output: 1.234568e+02   }
}

Output:

123.456789
123.46
123
Hello
1.234568e+02

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